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first step to a more flexible dotile() algorithm

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This commit is contained in:
Anselm R. Garbe
2006-09-29 12:38:27 +02:00
parent a118a57fe3
commit 14d05e7c72
7 changed files with 52 additions and 35 deletions
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58
view.c
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@ -65,6 +65,8 @@ togglemax(Client *c)
/* extern */
void (*arrange)(Arg *) = DEFMODE;
Bool isvertical = VERTICALSTACK;
StackPos stackpos = STACKPOS;
void
detach(Client *c) {
@ -97,35 +99,37 @@ dofloat(Arg *arg) {
/* This algorithm is based on a (M)aster area and a (S)tacking area.
* It supports following arrangements:
*
* MMMS MMMM
* MMMS MMMM
* MMMS SSSS
*
* The stacking area can be set to arrange clients vertically or horizontally.
* Through inverting the algorithm it can be used to achieve following setup in
* a dual head environment (due to running two dwm instances concurrently on
* the specific screen):
*
* SMM MMS MMM MMM
* SMM MMS MMM MMM
* SMM MMS SSS SSS
*
* This uses the center of the two screens for master areas.
* MMMS MMMM SMMM
* MMMS MMMM SMMM
* MMMS SSSS SMMM
*/
void
dotile(Arg *arg) {
int h, i, n, w;
Client *c;
w = sw - mw;
for(n = 0, c = nexttiled(clients); c; c = nexttiled(c->next))
n++;
if(n > 1)
h = (sh - bh) / (n - 1);
else
h = sh - bh;
if(isvertical) {
if(stackpos == StackBottom) {
w = sw;
if(n > 1)
h = (sh - bh) / (n - 1);
else
h = sh - bh;
}
else {
w = sw - master;
if(n > 1)
h = (sh - bh) / (n - 1);
else
h = sh - bh;
}
}
else { /* horizontal stack */
}
for(i = 0, c = clients; c; c = c->next) {
if(isvisible(c)) {
@ -143,11 +147,11 @@ dotile(Arg *arg) {
else if(i == 0) {
c->x = sx;
c->y = sy + bh;
c->w = mw - 2 * BORDERPX;
c->w = master - 2 * BORDERPX;
c->h = sh - 2 * BORDERPX - bh;
}
else if(h > bh) {
c->x = sx + mw;
c->x = sx + master;
c->y = sy + (i - 1) * h + bh;
c->w = w - 2 * BORDERPX;
if(i + 1 == n)
@ -156,7 +160,7 @@ dotile(Arg *arg) {
c->h = h - 2 * BORDERPX;
}
else { /* fallback if h < bh */
c->x = sx + mw;
c->x = sx + master;
c->y = sy + bh;
c->w = w - 2 * BORDERPX;
c->h = sh - 2 * BORDERPX - bh;
@ -228,14 +232,14 @@ resizecol(Arg *arg) {
return;
if(sel == getnext(clients)) {
if(mw + arg->i > sw - 100 || mw + arg->i < 100)
if(master + arg->i > sw - 100 || master + arg->i < 100)
return;
mw += arg->i;
master += arg->i;
}
else {
if(mw - arg->i > sw - 100 || mw - arg->i < 100)
if(master - arg->i > sw - 100 || master - arg->i < 100)
return;
mw -= arg->i;
master -= arg->i;
}
arrange(NULL);
}